题解 | 日期差值

#include<bits/stdc++.h>
using namespace std;
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int b[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
bool isLeapYear(int year){
	return (year%400==0)||(year%4==0&&year%100!=0);
}
int sum1=0,sum2=0;
int input1,input2;
int year1,month1,day1,year2,month2,day2;
int main(){
	cin>>input1>>input2;
	year1=input1/10000;
	year2=input2/10000;
	month1=(input1/100)%100;
	month2=(input2/100)%100;
	day1=input1%100;
	day2=input2%100;

	
	for(int i=0;i<year1;i++){
		if(isLeapYear(i)){
			sum1+=366;
		}else{
			sum1+=365;
		}
	}
	if(isLeapYear(year1)){
		a[2]=29;
	}
	for(int i=1;i<month1;i++){
		sum1+=a[i];
	}
	sum1+=day1;
	
	
	for(int i=0;i<year2;i++){
		if(isLeapYear(i)){
			sum2+=366;
		}else{
			sum2+=365;
		}
	}
	if(isLeapYear(year2)){
		b[2]=29;
	}
	for(int i=1;i<month2;i++){
		sum2+=b[i];
	
	}
	sum2+=day2;

    cout<<max(sum1,sum2)+1-min(sum1,sum2);


}