题解 | 日期差值
日期差值
https://www.nowcoder.com/practice/ccb7383c76fc48d2bbc27a2a6319631c
from datetime import datetime, timedelta, date
def fun(s):
return s[:4], s[4:6], s[6:]
s1 = input()
s2 = input()
y1, m1, d1 = fun(s1)
y2, m2, d2 = fun(s2)
dt1 = datetime(int(y1), int(m1), int(d1))
dt2 = datetime(int(y2), int(m2), int(d2))
print((dt2 - dt1).days+1)
其实能找到就很好了，当然收支能抵