题解 | 单组_spj判断数组之和
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
#include <stdio.h> int main() { int base=1; long long n,m; scanf("%lld %lld",&n,&m); long long remainder=m-n; long long extra=remainder/n; long long additional=remainder%n; for(int i=0;i<n;i++){ if(i<additional) printf("%lld ",base+extra+1); else printf("%lld ",base+extra); } return 0; }