题解 | 字符串的反码
字符串的反码
https://www.nowcoder.com/practice/01b7dae14d1b464db5f9259e90d9a35e
def revword(s): res = [] for i in range(len(s)): if ord('A') <= ord(s[i]) and ord(s[i]) <= ord('Z'): a = ord(s[i]) - ord('A') r = ord('Z') - a res.append(chr(r)) elif ord('a') <= ord(s[i]) and ord(s[i]) <= ord('z'): a = ord(s[i]) - ord('a') r = ord('z') - a res.append(chr(r)) # elif ord('a') == ord(s[i]): # res.append('z') # elif ord('z') == ord(s[i]): # res.append('a') else: res.append(s[i]) return ''.join(res) s = input() print(revword(s))