题解 | 打印日期

#include <stdio.h>
 int day[2][31]={{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};
 int isleapyear(int i){
    if((i%4==0&&i%100!=0)||i%400==0)
    return 1;
    else return 0;
 }
int main() {
    int i,j;
    scanf("%d %d",&i,&j);
    int t=isleapyear(i);
    int m,sum=0;
    for(m=1;m<=12;m++){
        sum+=day[t][m];
        if(sum>=j)
            break;
    }
    int q=m;
    while(j>0)
        j-=day[t][q--];
        j+=day[t][m];
    printf("%d-%02d-%02d",i,m,j);
    return 0;
}