题解 | 获得积分最多的人(一)
获得积分最多的人(一)
https://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
select
name,
sum(grade_num) over (
partition by
user_id
order by
user_id
) as grade_num
from
grade_info
inner join user on grade_info.user_id = user.id
order by grade_num desc
limit 1
