题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
'''
a='aabcddd'
b=a.replace('b','')
print(b)
print(a.count('d'))
'''
string=str(input())
cnt={}
for i in string:
cnt[i]=string.count(i)
cnt_min=min(cnt.values())
#print(cnt_min)
for key in cnt.keys():
if cnt[key]==cnt_min:
string=string.replace(key,'')
print(string)
投递字节跳动等公司9个岗位
