最简单的一集

牛客的课程订单分析(七)

https://www.nowcoder.com/practice/d6f4a37f966145da8900ba9edcc4c068

select source, count(1) cnt
from (select ifnull(name, 'GroupBuy') source, count(product_name) over (partition by user_id) rk
      from order_info o
               left join client c on o.client_id = c.id
      where date > '2025-10-15'
        and product_name in ('Python', 'C++', 'Java')
        and status = 'completed') a
where rk > 1
group by source
order by source;

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