题解 | #字符串合并处理#

# 2024年11月5日   周二   上午11:54
# wujie
s1, s2 = input().split()

s = s1 + s2

s3 = ""
s4 = ""
for i in range(len(s)):
    if i % 2 == 0:
        s3 += s[i]
    elif i % 2 == 1:
        s4 += s[i]

s5 = sorted(s3)
s6 = sorted(s4)


# “abcedf”
s7 = ""
for i in range(len(s)):
    # print(i,end = ' ')
    if i % 2 == 0:
        s7 += s5[i // 2]
    else:
        s7 += s6[i // 2]

s8 = ""
for i in s7:
    if (
        ord("0") <= ord(i) <= ord("9")
        or ord("A") <= ord(i) <= ord("F")
        or ord("a") <= ord(i) <= ord("f")
    ):
        t = (bin(int(i, 16))[2:].zfill(4))[::-1]  # 注意这里的写法
        tt = (hex(int(t, 2))[2:]).upper()
        s8 += tt
    else:
        s8 += i
print(s8)