题解 | #提取不重复的整数#

def remove_duplicate():
    n = int(input())
    n_list = list(str(n))
    n_list.reverse()     # 先把列表顺序颠倒
    new_list = []
    for i in n_list:
        if i not in new_list:
            new_list.append(i)
    new_n=0
    for j in range(len(new_list)):
        new_n=new_n+int(new_list[j])*(10**(len(new_list)-1-j))
        j=j+1
    print(new_n)

remove_duplicate()