题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
int main()
{
double test(int x);
int a, b;
scanf("%d",&a);
double z;
z=(double)test(a);
printf("%.1f",z);
return 0;
}
double test(int x)
{
int i;
int y;
double c=0,e=0;
for(i=0;i<x;i++)
{
scanf("%d",&y);
if(y<=60)
{
c=c+0.1;
}
if(y>60)
{
e=e+0.2;
}
}
return c+e;
}
#牛客创作赏金赛#
