题解 | #字符串排序#
字符串排序
https://www.nowcoder.com/practice/5190a1db6f4f4ddb92fd9c365c944584
# 2024年10月19日 下午18:35
# A Famous Saying: Much Ado About Nothing (2012/8).
# A aaAAbc dFgghh: iimM nNn oooos Sttuuuy (2012/8).
s = input()
a = ''
for i in s:
if i.isalpha():
a += i
#print(a)
b = sorted(a,key=str.upper)
#print(*b)
res = ''
idx = 0
for i in range(len(s)):
if s[i].isalpha():
res += b[idx]
idx += 1
else:
res += s[i]
print(''.join(res))
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