题解 | #数位之和#
数位之和
https://www.nowcoder.com/practice/5e85cc26475449648e668aa98e92d05b
#include <stdio.h>
int main() {
long long num = 0;
scanf("%lld",&num);
long long i = 10;
long long result = 0;
while (num % (i/10) != num)
{
result += (num % i - result) / (i/10) ;
i *= 10;
}
printf("%lld\n",result);
return 0;
}
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