题解 | #HJ19 简单错误记录#

import sys

error_dic = {}
error_list = []

for line in sys.stdin:
    file_path, row_num = line.split()
    file_name = file_path.split("\\")[-1][-16:]
    error_key = file_name + " " + row_num

    if error_key in error_dic:
        error_dic[error_key] += 1
    else:
        error_dic[error_key] = 1
        error_list.append(error_key)

for error_key in error_list[-8:]:
    print(error_key, error_dic[error_key])

# 说明:
# 使用字符串作为error_key，保证唯一性。
# 在error_key不在error_dic的情况下，把它添加到error_list，保证元素不重复，也满足了第一次出现。





# 方法二：使用元组作为error_key
# import sys

# input_list = []
# error_dic = {}

# for line in sys.stdin:
#     file_path, row_num = line.split()
#     file_name = file_path.split("\\")[-1][-16:]
#     error_key = (file_name, row_num)

#     if error_key not in error_dic:
#         error_dic[error_key] = 1
#     else:
#         error_dic[error_key] += 1

# output = []
# for k, v in error_dic.items():
#     output.append([k[0], k[1], v])

# for li in output[-8:]:
#     print(li[0], li[1], li[2])