题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
# 20240919
while True:
try:
n = int(input())
ls = input().split()
k = int(input())
if k != 0:
print(ls[-k])
else:
print(0)
except:
break
