题解 | #求int型正整数在内存中存储时1的个数#

#include <iostream>
#include <math.h>
 using namespace std;

int main ()
{
    int num, cnt = 0,flag = 1;
    cin >> num;

    while (flag){
        if (num % 2 != 0){
           cnt++;
        }
        
        num = num / 2;
        if (num == 1)
        {
            cnt++;
            flag = 0;
        }
    }
    cout << cnt <<endl;
    return 0;
}