题解 | #异常的邮件概率#
异常的邮件概率
https://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select
date,
round(1 - avg(if (type = 'completed', 1, 0)), 3) P
from
email e
join user u1 on e.send_id = u1.id
join user u2 on e.receive_id = u2.id
where
u1.is_blacklist = 0
and u2.is_blacklist = 0
group by
date
order by
date
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