题解 | #简单计算器#
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include <math.h> #include <stdio.h> int main() { double_t a,b;//要用双精度浮点数 char ch; scanf("%lf%c%lf",&a,&ch,&b); switch (ch) { case '+': printf("%.4lf+%.4lf=%.4lf\n",a,b,a+b); break; case '-': printf("%.4lf-%.4lf=%.4lf\n",a,b,a-b); break; case '*': printf("%.4lf*%.4lf=%.4lf\n",a,b,a*b); break; case '/': if(b==0.0) { printf("Wrong!Division by zero!\n"); } else { printf("%.4lf/%.4lf=%.4lf\n",a,b,a/b); } break; default: printf("Invalid operation!\n"); break; } return 0; }