题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型vector * @param target int整型 * @return int整型 */ int search(vector<int>& nums, int target) { // write code here int pos = nums.size()-1; int start=0,end=nums.size()-1; while ((end-start)>1 && nums.size()>2) { pos = (int)(start+end)/2; if (nums[pos]<target) { start=pos; }else if(nums[pos]>target){ end=pos; }else{ return pos; } } if (end - start == 1 || nums.size()==1) { return target==nums[start]?start:(target==nums[end]?end:-1); } return -1; } };