题解 | #单组_spj判断数组之和#
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
cout << (b - (a - 1) * 1) << " ";
for(int i=0; i<a-1; i++)
{
cout << 1 << " ";
}
}