题解 | #百鸡问题#

#include <iostream>
using namespace std;
int n;
int main() {
    cin>>n;
    int x,y;
    double z;
    for(x=0;x<=100;x++)
    {
        for(y=0;y<=100-x;y++)
        {
            z=100-x-y;
            if(z<0)continue;
            double k=z/3;
            if(5*x+3*y+k<=n)
            {
                cout<<"x="<<x<<","<<"y="<<y<<","<<"z="<<z<<endl;
            }
        }
    }
}
//花的钱可以少于n
//z注意要用float表示