题解 | #删除有序链表中重复的元素-I#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
 */
struct ListNode* deleteDuplicates(struct ListNode* head) {
    // write code here
    struct ListNode* top = head;
    while(head !=NULL&&head->next!=NULL){
        if(head->val == head->next->val){
            struct ListNode* freenode = head->next;
            head->next = head->next->next;
            free(freenode);
            continue;
        }
        head = head->next;
        }
    return top;
}