题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ #include <bits/types/struct_tm.h> class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ ListNode* reverseBetween(ListNode* head, int m, int n) { // write code here ListNode* list_head = head; // find right pos ListNode* start_node = nullptr; ListNode* right_node = head; ListNode* cursor_node = head; int size = 0; // find right_node and claim start_node if pos not equals 1 for (int i = 1; i <= n; i++, size++) { if (cursor_node == nullptr) { break; } if (i == n) { right_node = cursor_node; } if (m > 1 && i == m - 1) { start_node = cursor_node; } cursor_node = cursor_node->next; } // special condition: m equals 1, construct an empty node as head node if (nullptr == start_node && m == 1) { start_node = new ListNode(2000); start_node->next = head; } // save temp start_node->next ListNode* tmp_node = start_node->next; // start_node->next point to right_node start_node->next = right_node; // then tail insert while (tmp_node != right_node) { ListNode* tmp_next_node = tmp_node->next; tmp_node->next = right_node->next; right_node->next = tmp_node; tmp_node = tmp_next_node; } // special condition if (m == 1) { list_head = start_node->next; } else { list_head = head; } return list_head; } };