题解 | #输出二叉树的右视图#
输出二叉树的右视图
https://www.nowcoder.com/practice/c9480213597e45f4807880c763ddd5f0
import java.util.*;
public class Solution {
public int[] solve (int[] preOrder, int[] inOrder) {
//层次遍历输出最右边元素
if(preOrder.length <= 1) return preOrder;
Queue<TreeNode> queue = new LinkedList<>();
List<Integer> list = new LinkedList<>();
queue.add(creat(preOrder, 0, preOrder.length - 1, inOrder, 0, inOrder.length - 1));
while(!queue.isEmpty()){
int size = queue.size();//记录这一层有多少个节点
for(int i = 0; i < size; i ++){
TreeNode node = queue.poll();
if(i == size - 1) {//最后一个
list.add(node.val);
}
if(node.left != null) queue.add(node.left);
if(node.right != null) queue.add(node.right);
}
}
int[] result = new int[list.size()];
for(int i = 0; i < result.length; i++){
result[i] = list.get(i);
}
return result;
}
TreeNode creat(int[] pre, int leftPre, int rightPre, int[] in, int leftIn, int rightIn){
if(leftPre > rightPre || leftIn > rightIn) return null;
TreeNode root = new TreeNode(pre[leftPre]);
for(int i = leftIn; i <= rightIn; i ++){
if(in[i] == pre[leftPre]){
root.left = creat(pre, leftPre + 1, leftPre + i - leftIn, in, leftIn, i - 1);
root.right = creat(pre, i - leftIn + leftPre + 1, rightPre, in, i + 1, rightIn);
break;
}
}
return root;
}
}
