题解 | #牛客每个人最近的登录日期(二)#

select
    t2.name as u_n,
    t3.name as c_n,
    t1.date
from
    (
        select
            *,rank() over(partition by user_id order by date desc) as rk
        from
            login
    ) as t1
    join user as t2 on t1.user_id = t2.id
    join client as t3 on t1.client_id = t3.id
where
    t1.rk = 1
order by
    u_n asc;