题解 | #字符串排序#

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        Map<String, Integer> map = new TreeMap();
        while (sc.hasNext()) {
            String b = sc.nextLine();
            if (b.equals("")) continue;
            map.put(b, map.getOrDefault(b, 0) + 1);
        }
        map.forEach((k, v) -> {
            for (Integer i = 0; i < v; i++) {
                System.out.println(k);
            }
        });
    }
}

仅需要处理一下相同字符串的存储的问题