题解 | #记负均正#

#include <iostream>
#include <regex>
#include <string>
#include <iomanip>
using namespace std;

int main() {

    int n = 0;
    int num;
    int sum = 0;
    int count1 = 0;
    int count2 = 0;
    cin >> n;
    for (int i = 0; i < n; i++) {
        cin >> num;
        if (num > 0) {
            sum += num;
        } else if (num < 0) {
            count1++;
        } else {
            count2++;
        }

    }

    double result = 0.0;
    if (sum == 0) {
        result = 0;
    } else {
        result = sum * 1.0/ (n - count1 - count2) ;
    }

    cout << count1 << " " << std::fixed << std::setprecision(1) << result;


    return 0;

}