题解 | #无法更改的信息#(元组解包法)
无法更改的信息
https://www.nowcoder.com/practice/0fce92fc0c7046038c185c0b3e7ed996
name1=tuple(input().split()) name2=tuple(input().split()) print(name1) print(name2) print((*name1[:3],*name2[-3:]))
无法更改的信息
https://www.nowcoder.com/practice/0fce92fc0c7046038c185c0b3e7ed996
name1=tuple(input().split()) name2=tuple(input().split()) print(name1) print(name2) print((*name1[:3],*name2[-3:]))
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