两次inner join
确定最佳顾客的另一种方式（二）
https://www.nowcoder.com/practice/b5766f970ae64ac7944f37f5b47107aa
select c.cust_name,sum(ol.item_price*ol.quantity) total_price from OrderItems ol inner join Orders o inner join Customers c on ol.order_num= o.order_num and o.cust_id=c.cust_id group by c.cust_name having total_price >=1000 order by total_price
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