题解 | #链表中环的入口结点#
链表中环的入口结点
https://www.nowcoder.com/practice/253d2c59ec3e4bc68da16833f79a38e4
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param pHead ListNode类 * @return ListNode类 */ struct ListNode* EntryNodeOfLoop(struct ListNode* pHead ) { // write code here //if(pHead==NULL) // return NULL; struct ListNode* fast=pHead; struct ListNode* slow=pHead; while(fast){ slow=slow->next; if(fast->next==NULL) return NULL; fast=fast->next->next; if(fast==slow){ fast=pHead; while(fast!=slow){ fast=fast->next; slow=slow->next; } return fast; } } return NULL; }