题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h> int main() { int n=0; scanf("%d",&n); int arr[n]; float sum=0; for(int i=0;i<n;i++) { scanf("%d",&arr[i]); if(arr[i]>60) sum+=0.2; else sum+=0.1; } printf("%.1lf",sum); return 0; }