题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
import java.util.*;
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param target int整型
* @return int整型
*/
public int search (int[] nums, int target) {
// write code here
int n = nums.length;
if(n==0){
return -1;
}
int left =0,right = n-1;
while(left<=right){
int mid = (left+right)/2;
if(target>nums[mid]){
left = mid+1;
}else if(target<nums[mid]){
right = mid-1;
}else{
return mid;
}
}
return -1;
}
}
这里要注意是 left<=right,当数组的长度为1时就会出现left和right都是0,所以不能简单的使用<
