题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main() {
float n,h,m;
scanf("%f %f %f",&n,&h,&m);
if(m<=n*h)
{
printf("%d",(int)(n-(m/h)));//(类型）强制类型转换
}
return 0;
}
查看2道真题和解析