题解 | #异常的邮件概率#
异常的邮件概率
https://www.nowcoder.com/practice/d6dd656483b545159d3aa89b4c26004e
select `date`, round(sum(case type when 'no_completed' then 1 else 0 end)/count(date),3) from email where send_id=any(select id from user where is_blacklist=0) and receive_id=any(select id from user where is_blacklist=0) group by `date` order by `date` asc
