题解 | #dp# #单词拆分(一)#
单词拆分(一)
https://www.nowcoder.com/practice/c0d32c1ce5744472a01b2351a2c2767f
#coding:utf-8
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param dic string字符串一维数组
# @return bool布尔型
#
class Solution:
def wordDiv(self , s , dic ):
# write code here
n = len(s)
dp = [False for i in range(0, n + 1)]
dp[0] = True
for i in range(1, n + 1):
for j in range(0, len(dic)):
#
cur_str = dic[j]
if len(cur_str) <= i:
if cur_str == s[i - len(cur_str): i]:
dp[i] = dp[i - len(cur_str)]
print ("dp: ", dp)
return dp[n]

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