二叉树110|257|404
110平衡二叉树
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isBalanced(self, root: Optional[TreeNode]) -> bool:
if self.height(root) == -1:
return False
else:
return True
def height(self, node) -> int:
if not node:
return 0
height_left = self.height(node.left)
height_right = self.height(node.right)
if height_left == -1 or height_right == -1:
return -1
if abs(height_left - height_right) > 1:
return -1
else:
height_node = max(height_left, height_right) + 1
return height_node
257二叉树的所有路径
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def binaryTreePaths(self, root: Optional[TreeNode]) -> List[str]:
path = []
result = []
if not root:
return result
return self.traversal(root, path, result)
def traversal(self, node, path, result) -> List:
path.append(node.val)
if not node.left and not node.right:
path_str = "->".join(str(item) for item in path)
result.append(path_str)
return result
if node.left:
self.traversal(node.left, path, result)
path.pop()
if node.right:
self.traversal(node.right, path, result)
path.pop()
return result
404左叶子之和
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumOfLeftLeaves(self, root: Optional[TreeNode]) -> int:
return self.getSum(root)
def getSum(self, node) -> int:
if not node:
return 0
left_val = self.getSum(node.left)
right_val = self.getSum(node.right)
if node.left and not node.left.left and not node.left.right:
left_val = node.left.val
sum_left_leaves = left_val + right_val
return sum_left_leaves