题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
import sys
while True:
try:
# 正常输入的时候那就打印，不输入那就跳出
num = int(input())
nums = list(map(int, input().split()))
k = int(input())
print(nums[len(nums) - k])
except:
break
埋点都出来了