题解 | #合并二叉树#

合并二叉树

https://www.nowcoder.com/practice/7298353c24cc42e3bd5f0e0bd3d1d759

# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 
# @param t1 TreeNode类 
# @param t2 TreeNode类 
# @return TreeNode类
#
class Solution:
    
    def mergeTrees(self , t1: TreeNode, t2: TreeNode) -> TreeNode:
        # write code here
        if not t1: return t2
        if not t2: return t1
        head = TreeNode(t1.val+t2.val)
        head.left, head.right = self.mergeTrees(t1.left, t2.left), self.mergeTrees(t1.right, t2.right)
        return head    

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