题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n = 0; while(scanf("%d",&n) != EOF) { printf("%d\n", 1 << n); } return 0; }
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int n = 0; while(scanf("%d",&n) != EOF) { printf("%d\n", 1 << n); } return 0; }
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