题解 | #字符串排序#
字符串排序
https://www.nowcoder.com/practice/5190a1db6f4f4ddb92fd9c365c944584
list_str=list(input())
list_d=list(filter(lambda x:x.isalpha(),list_str))
list_ds=sorted(list_d,key=lambda x:x.lower())
for i in range(len(list_str)):
if list_str[i].isalpha():
list_str[i]=list_ds[0]
list_ds.pop(0)
print(*(list_str),sep="")
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