题解 | #求int型正整数在内存中存储时1的个数#

#include <iostream>
#include<vector>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> binary;
    while(n!=0){
        binary.push_back(n%2);  //获得二进制数的逆序
        n/=2;
    }
    int sum=0;
    for(int i=binary.size()-1;i>=0;i--){  //逆序检索1
        sum+=binary[i];
    }
    cout<<sum;
    return 0;
}