题解 | #牛牛的digit#
牛牛的digit
https://www.nowcoder.com/practice/21b49f1f495f4280b8a96c415deaa3c4
#include <stdio.h>
int digit(int x, int i) {
int n = 0;
if (i == 1) {
return x % 10;
} else {
return x % 10 + 10 * digit(x / 10, i - 1);
}
}
int main() {
int x = 0, i = 0;
scanf("%d %d", &x, &i);
printf("%d", digit(x, i));
return 0;
}
