题解 | #牛牛的通勤#
牛牛的通勤
https://www.nowcoder.com/practice/1fe33d534843473eb086c4b42655e13d
#include <stdio.h>
int main() {
int n=0;
scanf("%d",&n);
double t1=n;
double t2=n/10+10;
if(10*t1<10*t2)
printf("w");
else
printf("v");
return 0;
}