题解 | #百钱买百鸡问题#

#include<iostream>
using namespace std;

int main() {
    for (int i = 0; i <= 20; i++) {
        for (int j = 0; j <= 33; j++) {
            for (int k = 0; k <= 100;
                    k++) { //遍历所有可能的公鸡、母鸡、小鸡取值
                if (i + j + k == 100 &&
                        5 * i + 3 * j + double(k) / 3 == 100) { //鸡的总数等于100，且总共花了100元
                    cout << i << " " << j << " " << k << endl;
                }
            }
        }
    }
    return 0;
}