题解 | #树的子结构#
树的子结构
https://www.nowcoder.com/practice/6e196c44c7004d15b1610b9afca8bd88
import java.util.*;
/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
public class Solution {
public boolean HasSubtree(TreeNode root1,TreeNode root2) {
if(root1 == null || root2 == null) return false;
return Issame(root1, root2) || HasSubtree(root1.right, root2) || HasSubtree(root1.left, root2);
}
boolean Issame(TreeNode root1, TreeNode root2){
if(root2 == null) return true; //注意这两步的顺序
if(root1 == null) return false;
if(root1.val != root2.val) return false;
return Issame(root1.right, root2.right) && Issame(root1.left, root2.left);
}
}
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