题解 | #数值的整数次方#

class Solution {
public:
    double Power(double base, int exponent) {
        if (exponent < 0){	// 碰到幂指数为负值，则更新一下基数与幂指数，方便统一计算
            base = 1/base;
            exponent = -exponent;
        }
        double res = 1.0;
        for (int i = 0; i < exponent; ++i) {
            res*=base;
        }
        return res;
    }
};