题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution {
public:
double Power(double base, int exponent) {
if (exponent < 0){ // 碰到幂指数为负值，则更新一下基数与幂指数，方便统一计算
base = 1/base;
exponent = -exponent;
}
double res = 1.0;
for (int i = 0; i < exponent; ++i) {
res*=base;
}
return res;
}
};
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