题解 | #字符串反转#
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
num = str(input()) l = len(num) ans = "" for i in range(0, l): ans += str(num[l - i - 1]) print(ans)
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
num = str(input()) l = len(num) ans = "" for i in range(0, l): ans += str(num[l - i - 1]) print(ans)
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