题解 | #简单密码#

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s;
    getline(cin, s);
    for (int i = 0; i < s.size(); i++) {
        if (s[i] >= 'a' && s[i] <= 'z') {
            switch (s[i]) {
                case 'a':
                case 'b':
                case 'c':
                    s[i] = '2';
                    break;
                case 'd':
                case 'e':
                case 'f':
                    s[i] = '3';
                    break;
                case 'g':
                case 'h':
                case 'i':
                    s[i] = '4';
                    break;
                case 'j':
                case 'k':
                case 'l':
                    s[i] = '5';
                    break;
                case 'm':
                case 'n':
                case 'o':
                    s[i] = '6';
                    break;
                case 'p':
                case 'q':
                case 'r':
                case 's':
                    s[i] = '7';
                    break;
                case 't':
                case 'u':
                case 'v':
                    s[i] = '8';
                    break;
                case 'w':
                case 'x':
                case 'y':
                case 'z':
                    s[i] = '9';
                    break;
            }
        } else if (s[i] >= 'A' && s[i] <= 'Z') {
            s[i] -= 'A' - 'a';
            if (s[i] == 'z')
                s[i] = 'a';
            else
                s[i] += 1;
        } else {
            continue;
        }
    }
    cout << s;
}
// 64 位输出请用 printf("%lld")