题解 | #跳台阶# | C++
跳台阶
https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param number int整型
* @return int整型
*/
int jumpFloor(int number) {
int one = 1, two = 2;
if (number < 3) return number;
int ans = 0;
for (int i = 3; i <= number; i++) {
ans = one + two;
one = two;
two = ans;
}
return ans;
}
};
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