题解 | #牛牛的digit#
牛牛的digit
https://www.nowcoder.com/practice/21b49f1f495f4280b8a96c415deaa3c4
#include<stdio.h>
#include<string.h>
int main()
{
char x[100] = { 0 };
int i = 0;
scanf("%s", x);
int len = strlen(x);
scanf("%d", &i);
int j = i;
while (i)
{
printf("%c", x[len-j]);
len++;
i--;
}
return 0;
}
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